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a fost răspuns

Media geometrică a numerelor
a=✓3-1÷2
b=✓3+1

Răspuns :

Cristeach
Mg=√a·b
Mg=√(√3-1)·√(√3+1)/2=√(3-1)/√2=√2/√2=1


[tex]\it m_g = \ \sqrt{a\cdot b} = \sqrt{\dfrac{\sqrt3-1}{2}\cdot(\sqrt3+1)} = \\\;\\ \\\;\\ = \sqrt{\dfrac{(\sqrt3-1)(\sqrt3+1)}{2}} = \sqrt{\dfrac{3-1}{2}} = \sqrt{\dfrac{2}{2}} =1[/tex]