AE=x si EB=y=> x+y=25 dam=>x=25-y
In triunghiul ACB aplicam teorema inaltimii=> CE²=AEₓEB=> 12²=xy=>144=xy
(25-y)y=144
25y-y²=144=>y²-25y+144=0
Ecuatie de gr al II-lea se rezolva cu Δ
Solutia este y=16 dar si y=9
sau y²-16y-9y+144=y(y-16)-9(y-16)=(y-16)(y-9)
(y-16)(y-9)=0=>y=16 si y=9.....se calculeaza AE=25-16=9dam
