r+c+k=106 kg
r=c+28
k=c+r+14
r /---/+28
c /---/
k /---/---/+28+14
106-(28+28+14)= 106-70= 36
36 : 4 = 9 (un segment egal)
r = 9+28=37 kg (rosii)
c = 9 kg (ceapa)
k=2×9+28+14=18+28+14=60 kg (cartofi)
verificare:
37+9+60=106
raspuns:
37 kg rosii
9 kg cepa
60 kg cartofi