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Antoniaanastasiu18
a fost răspuns

2·x+4·x+...+3986·x= 1993·1994 Rezolvati ecuatia va rog imi trebuue urgent!!!

Răspuns :

Rayzen
2·x+4·x+...+3986·x= 1993·1994
x·(2+4+...+3986) = 1993·1994
2·x·(1+2+...+1993) = 1993·1994
2·x·(1993·1994)\2 = 1993·1994 
x·(1993·1994) = 1993·1994 

=> x = 1
Letitiasqn
2x + 4x + ... + 3986x = 1993 × 1994 →

x( 2 + 4 + ... + 3986) = 1993 × 1994 →
2x( 1 + 2 + ... + 1993) = 1993 × 1994 →

2x ×(1993 × 1994)/3 = 1993 × 1994 →
x × 1993 × 1994 = 1993 × 1994 →
x =( 1993 × 1994)/ (1993 × 1994) →x = 1

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