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Dezzy00
a fost răspuns

Fie functia f:R→R,f(x)=2x+1.Calculati f(-2)+f(-1)+f(0)+f(1)

Răspuns :

SignOfTheTimes
Bună,

f : |R → |R
f(x) = 2x+1

f(-2) = 2•(-2)+1 = -4+1 = -3.
f(-1) = 2•(-1)+1 = -2+1 = -1.
f(0) = 2•0+1 = 0+1 = 1.
f(1) = 2•1+1 = 2+1 = 3.

f(-2)+f(-1)+f(0)+f(1) = -3-1+1+3 = -4+4 = 0.


Succes!
AnaAnaIulia
f(-2)=2*(-2)+1=-4+1=-3
f(-1)=2*(-1)+1=-2+1=-1
f(0)=2*0+1=0+1=1
f(1)=2*1+1=2+1=3

f(-2)+f(-1)+f(0)+f(1)= -3+(-1)+1+3=-3-1+1+3=-4+1+3=-3+3=0

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