Răspuns :
AC²=AB²+BC² ;AC²=3²+4² ;AC²=9+16=25 ;aC=5cm
H=CC'
H²=(AC')²-AC²=13²-5²=144
H=√144=12cm
H=CC'
H²=(AC')²-AC²=13²-5²=144
H=√144=12cm
Diagonala paralelopipedului dreptunghic = √(L²+l²+h²)
⇒ 13 = √ (9+16+h²) | ( )²
169 = 9+16+h²
h² = 169-9-16
h = √(144) = 12 (cm)
⇒ 13 = √ (9+16+h²) | ( )²
169 = 9+16+h²
h² = 169-9-16
h = √(144) = 12 (cm)