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DenisAK40
a fost răspuns

Simplificati fractia [tex] \frac{9 x^{2}-16 }{18 x^{2}-48x-32 } [/tex]

Răspuns :

Rayzen
[tex] \\ \dfrac{9x^2-16}{18x^2-48x+32} = \dfrac{(3x-4)(3x+4)}{2\cdot(9x^2-24x+16)} = \dfrac{\textbf{(3x-4)}(3x+4)}{2\cdot\textbf{(3x-4)}^2} = \\ \\ = \dfrac{3x+4}{2\cdot(3x-4)} \\ \\ [/tex]
Albatran
cu -32 nu se simplifica
 modificam , sa se simplifice
18x²-48x+32= 2(9x²-24x+16) =2(3x+4)²




(3x-4)(3x+4)
__________
2(3x-4)²

Conditiide existenta x≠4/3
atunci , prin simplificare cu (3x-4), expresia devine

 3x+4
____
2(3x-4)

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