Răspuns :
|2x-1|≤4 => -4 ≤ 2x-1 ≤ 4 |+1 => -3 ≤ 2x ≤ 5 |:2 => -3/2 ≤ x ≤ 5/2
=> x ∈ [-3/2, 5/2]
=> x ∈ [-3/2, 5/2]
Bună,
|2x-1| ≤ 4.
-4 ≤ 2x-1 ≤ 4 /+1
-3 ≤ 2x ≤ 5 /:2
-3/2 ≤ x ≤ 5/2
x € [-3/2;5/2].
Succes!
|2x-1| ≤ 4.
-4 ≤ 2x-1 ≤ 4 /+1
-3 ≤ 2x ≤ 5 /:2
-3/2 ≤ x ≤ 5/2
x € [-3/2;5/2].
Succes!