[tex]n= C^2_{25}= \frac{25!}{2!23!}= \frac{24*25}{2}=12*25=300 \\ a)m= C^2_{10}= \frac{10!}{2!81}= \frac{9*10}{2}=9*5=45 \\ P(A)= \frac{m}{n} = \frac{45}{300}= \frac{3}{20} \\ b)m= C^2_{15}= \frac{15!}{2!13!}= \frac{14*15}{2}=7*15=105 \\ P(B)= \frac{105}{300}= \frac{7}{20} [/tex]