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Determinati volumul de NaOH de concentratie 20 % , densitatea = 1,2g/cm3 ce reactioneaza cu 2 moli de glicina .
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Răspuns :

[tex]\displaystyle NH_2-CH_2-COOH \ + \ NaOH \ = \ NH_2-CH_2-COONa \ + \ H_2O \\ \\ M_{NH_2-CH_2-COOH}=75g/mol \\ \\ m_{NH_2-CH_2-COOH}=2\cdot 75=150g \\ \\ M_{NaOH}=40g/mol \\ \\ 75g..........40g \ NaOH \\ \\ 150g..........x \ g \ NaOH \\ \\ x=2\cdot 40=80g \\ \\ c=\frac{100x}{m_s}=\textgreater m_s=\frac{100x}{c}=400g \\ \\ \rho=\frac{m_s}{V_s}=\textgreater V_s=\frac{m_s}{\rho}=333,33cm^3[/tex]

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