[tex]\displaystyle NH_2-CH_2-COOH \ + \ NaOH \ = \ NH_2-CH_2-COONa \ + \ H_2O \\ \\ M_{NH_2-CH_2-COOH}=75g/mol \\ \\ m_{NH_2-CH_2-COOH}=2\cdot 75=150g \\ \\ M_{NaOH}=40g/mol \\ \\ 75g..........40g \ NaOH \\ \\ 150g..........x \ g \ NaOH \\ \\ x=2\cdot 40=80g \\ \\ c=\frac{100x}{m_s}=\textgreater m_s=\frac{100x}{c}=400g \\ \\ \rho=\frac{m_s}{V_s}=\textgreater V_s=\frac{m_s}{\rho}=333,33cm^3[/tex]
