Daca V are coordonatele 1,-2 inseamna ca :
1)-b/2a=-(-2m²/2)=1=>
m²=1 => m1=-1 si m2=1 S1={-1,1}
2)-Δ/4a=-(4m^4-4*(m-2))/4=-2
(4m^4-4m+8)/4=2
m^4-m+2=2
m^4-m=0
m*(m³-1)=0
m*(m-1)(m²+m+1)=0
m1=0
m2=1
Paranteza e strict pozitiva pt ca determinantul acesteia este -3<0
S2={0,1]
S1∩S2=1
m=1
