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Nicogaga12
a fost răspuns

In ecuatiile moleculare ale reactiilor date stabileste coeficientii si scrie-le in forma ionica completa si ionica redusa:
a) KOH+H2SO4→ K2SO4+H2O b) NaOH+CuCl2→ Cu(OH)2+NaCl c) K2CO3+HCl →KCl+H2O+CO2↑

Răspuns :

Anaursu1999
a) 2KOH+H2SO4=K2SO4+2H2O
2K+ +2OH- +2H+ +So4²- →2k+ +so4²- +2h2o
2OH- + 2H+ → 2H2O

b) 2NaOH+CuCl2→Cu(OH)2↓ + 2NaCl
2Na+ +2OH- +Cu²+ +2Cl- Cu(OH)2↓+ 2Na+ +2Cl
2OH- + Cu²+ →Cu(OH)2↓

c) K2CO3+2HCl→2KCl+H2O+CO2↑
2K+ +CO3²- +2H+ +2Cl- → 2K+ 2Cl- +CO2↑+H2O
CO3²- +2H+ → CO2↑+H2O

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