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CorinaStg
a fost răspuns

Efectuati: -123+128÷[(-2)la puterea 17÷2 la puterea 12+2×(-2)la puterea a 6×2 la puterea a 3÷(-2)la puterea a 5]

Răspuns :

Renatemambouko
-123+128÷[(-2)¹⁷÷2¹²+2×(-2)⁶×2³÷(-2)⁵]=
=-123+2⁷÷[-(2)⁵+2×2⁹÷(-2)⁵]=
=-123+2⁷÷[-2⁵-2¹⁰÷2⁵]=
=-123+2⁷÷(-2⁵-2⁵)=
=-123+2⁷÷(-2⁶)=
=-123-2=-125=-5³

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