in primul rand pui conditia ca Δ=m²-8>0 m²-8=0 m1=-2√2 m2=2√2 m∈(-∞,-2√2)U(2√2,∞) Solutiile x1,x2 trebuie sa fie ≥1 x1≥1 x2≥1=> x1+x2≥1+1=2 Dar x1+x2=-m conf Viet=> -m≥2=> m≤-2 m∈(-∞,-2] Intersectezi rezultatele m∈(-∞, -2√2)U(2√2,+∞)∩(-∞,-2]=(-∞,-2√2)
