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a fost răspuns

2 2
(x+2) +3(x-1)(x+1)=(2x-1)

Răspuns :

Iakabcristina2
x+2+3x²-3=2x-1
3x²+x-1=2x-1
3x²+x-2x=0
3x²-x=0
x(3x-1)=0
(x+2)+3(x-1)(x+1)=(2x-1)
x+2+3(x²-1)=2x-1
x+2+3x²-3=2x-1
3x²+x-1=2x-1
3x²+x-1-2x+1=0
3x²-x=0
x(3x-1)=0
x1=0
3x-1=0 <=> 3x=1 <=> x2=1/3

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