Răspuns :
Inaltimea piramidei=√(13²-5²)=12cm
latura bazei=2 apotema bazei =2*5=10cm
V= Ab*h/3= 10²*12/3=400cm³
aria sectiunii diagonale (triunghi isoscel , baza =diagnala bazei, inaltime=inaltimea piramidei) =baza*h/2= 10√2*12/2=(10√2)*6=60√2cm²
alateral =Perimetrul bazei *apotema piramidei/2= 4*10*13/2= 2*130=260cm²
latura bazei=2 apotema bazei =2*5=10cm
V= Ab*h/3= 10²*12/3=400cm³
aria sectiunii diagonale (triunghi isoscel , baza =diagnala bazei, inaltime=inaltimea piramidei) =baza*h/2= 10√2*12/2=(10√2)*6=60√2cm²
alateral =Perimetrul bazei *apotema piramidei/2= 4*10*13/2= 2*130=260cm²