Se da:
[tex]m_{2}-m_{1}=125g=0,125kg\\
p_{2}=1 \frac{g}{cm^{3}}= 1000\frac{kg}{m^{3}} \\
p_{1}=0,8 \frac{g}{cm^{3}}=800 \frac{kg}{m^{3}} \\
V_{0}=?\\
[/tex]
Formule:
[tex]m_{2}=m_{l_{2}}+m_{0}\\
m_{2}=V_{l_{2}}*p_{2}+m_{0}\\ [/tex]
Acelasi lucru cu m1:
[tex]m_{1}=V_{l_{1}}*p_{1}+m_{0}\\[/tex]
Daca ne uitam mai atent, observam ca [tex] V_{l_{2}}=V_{l_{1}}=V_{0};[/tex]
De unde scoatem formula:
[tex]m_{2}-m_{1}=125\\
V_{0}*p_{2}+m_{0}-(V_{0}*p_{1}+m_{0})=125\\
V_{0}*p_{2}+m_{0}-V_{0}*p_{1}-m_{0}=125\\
V_{0}*p_{2}-V_{0}*p_{1}=125\\
V_{0}*(p_{2}-p_{1})=125\\
V_{0}= \frac{125}{p_{2}-p_{1}}
[/tex]
Calcule:
[tex]V_{0}= \frac{0,125}{1000-800} =0,000625m^{3}=625cm^{3}\\[/tex]
