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Andry
a fost răspuns

Calculati media geometrica anumerelor
x= 2√18+3√12

y= [tex] \frac{12}{√8+√12} [/tex]

Răspuns :

x=2×3×√2+3×2×√3=6√2+6√3=6(√2+√3)
u=12(√8-√12)/(8-12)=12(2√2-2√3)/(-4)=-3×2(√2-√3)=-6(√2-√3)=6(√3-√2)
[tex] M_{g}= \sqrt{xy}= \sqrt{6( \sqrt{2}+ \sqrt{3} )*6( \sqrt{3}- \sqrt{2}) } = \sqrt{36}=6 [/tex]

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