5 mere si 10 pere
In 5 zile a cules cate 2 pere si au aparut 5 mere in pom
5 mere existente + 5 mere aparute in cele 5 zile = 10 mere
10 mere - 2 mere + 1 mar ( ce apare in acelasi timp) = 9 mere raman
9 mere - 2 mere + 1 mar = 8 mere
8 mere - 2 mere + 1 mar = 7 mere exista in pom, dupa cele 3 zile in care culege cate 2 mere
7 mere - 2 mere + 1 = 6 mere
6 mere - 2 mere + 1 = 5 mere
5 mere - 2 mere + 1 = 4 mere
4 mere - 2 mere + 1 = 3 mere
3 mere - 2 mere + 1 = 2 mere
2 mere - 2 mere + 1 mar ( ce apare in acelasi timp) = 1 mar existent in pomul vrajit, dupa ce a cules in 5 zile cate 2 pere si in 9 zile cate 2 mere
5 zile + 9 zile = 14 zile
Raspuns: dupa 14 zile pomul vrajit ramane cu un singur fruct