1. nr.at. = n·N Av. = 7·6,023·10²³ = 42,161·10²³ atomi Zn
2. n m/M = 365/36,5 = 10 moli
3. a) n = 10/12 = 5/6 moli = 5/6 ·6,022·10²³ atomi = 5,018·10²³ atomi
1atom( nucleu) C......contine .........6 neutroni
5,018·10²³......................................x = 30,11·10²³ neutroni
b) Z Mg = 12 n = 12/24 = 0,5 moli nr. at. = 0,5·6,022·10²³ = 3,011·10²³
1atom................12 neutroni
3,011·10²³................x = 36,132·10²³ neutroni
4. %C = mC·100/M
CH4 %C = 12·100/16 = 75%
K2CO3 %C = 12·100/126 = 9,5238%
