Răspuns :
Notam cu i,a,m sumele cheltuite de ion, andrei si mihai
i=a+11=m+11 (pt ca a=m)
a=m
a+m+i=86
=>m+m+m+11=86
3m+11=86
3m=86-11
3m=75
m=75:3
m=25 lei a cheltuit mihai
i=m+11=25+11=36 lei a cheltuit ion
a=m=25 lei a cheltuit andrei
i=a+11=m+11 (pt ca a=m)
a=m
a+m+i=86
=>m+m+m+11=86
3m+11=86
3m=86-11
3m=75
m=75:3
m=25 lei a cheltuit mihai
i=m+11=25+11=36 lei a cheltuit ion
a=m=25 lei a cheltuit andrei
ion=a,Andrei=b,mihai=c. a+b+c=86
a+a+11+a+11=86 = 3a+22=86 =. 3a=64= a=21,(3) ;b=32,(3);c=43,(3)
a+a+11+a+11=86 = 3a+22=86 =. 3a=64= a=21,(3) ;b=32,(3);c=43,(3)