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Descompuneti in factori: x³-8; -27+x³; 8a3+125b³; a3-64b³.

Răspuns :

Renatemambouko
x³-8 =(x-2)(x²+2x+4)
-27+x³ =x³-3³=(x-3)(x²+3x+9)
8a³+125b³ =2³a³+5³b³=(2a+5b)(4a²-10ab+25b²
a³-64b³=a³-2³b³=(a-2b)(a²+2ab+4b²)

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