11. nCO2 = 13,2/44 = 0,3 moli = nC mC = 0,3x12 = 3,6g
nH2O = 5,85/18 = 0,325moli nH = 0,65 mH = 0,65g
mC + mH = 4,25g ⇒ substanta = hidrocarbura
M = 5,862x28,9 = ≈ 170g/mol
CxHy 12x +y = 170
12x/y = 3,6/0,65 12x = 3,6y/0,65 360y/65 + y = 170 425y = 11050 y = 26
x = 0,3x26/0,65 =12
hidrocarbura : C12H26
