I-2 .Puui conditia ca f(x)=g(x)
2x-3=x+1=>
2x-x=3+1
x=4
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lll-2b) Aria=∫x²/(x+1)dx x∈[0,1]
Se prelucreaza expresia dupa integrala
x²/(x+1)=(x²-1+1)/(x+1)=(x²-1)/(x+1)+1/(x+1)=(x-1)*(x+1)/(x+1)+1/(x+1)=
x-1+1/(x+1)
revii la Arie
Aria=∫(x-1)dx+∫dx/(x+1)=∫xdx-∫dx+ln(x+1)
x²/2-x+ln(x+1)].0↑1=(1/2-1+ln2)-(0/2-0+ln1)=ln2-1/2
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Fie F(x)+c o primitiva a lui f.Atunci F `(x)=f(x)=x²/(x+1)
x²≥0 pt x>-1
(x+1)>0 pe acelasi interval
Daca derivata f (x)>0 atunci primitiva F este crescatoare .=> F(x)+c este crescatoare
