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Rezolvați in |N ecuatia:x+3x+5x+...+99x=2x+4x+...+100x-50

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Saoirse1
X(1+3+5+....99)=2x(1+2+3+....50) -50 ; suma 1+3+5+...99 are 50 termeni , aplicam formula s= nr te ternmeni la puterea2 atunci 1+3+5+...99=50². 1+2+...50=50*51/2=25*51=1275. Ecuatia devine 2500x=2x*1275 -50 ; 2500x-2550x=-50 ;;-50x=-50 deci x=1

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