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a fost răspuns

Care este reactie cu procentajele de 60.579% O. 17.72%N . 15.189% C .6.32% H

Răspuns :

60,579/16=3,786
17,72/14=1,265
15,189/12=1,265
6,32/1=6,32

3,786/1,265=3 atomi O
1,265/1,265=1 atom N
1,265/1,265=1atom C
6,32/1,265=5 atomi H

Substanta este : NH4HCO3-carbonat acid de amoniu

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