Abc = tr. drpt => (T.p) : 1.AB= 6 cm = 2×3
2.AC= 8 cm = 4×2
Din 1. si 2. => BC = 5×2 = 10 cm
Stiind ca AD= inaltime ( inaltimea imparte ipotenuza in 2 parti egale ) => BD=DC = 5 cm => ( T.î ) AD² = DB× DC => AD² = 5×5 = 10 => AD = √10 ( si de aicea vezi tu cat face √10 ) .
