Aducem numerele a și b la forme mai simple.
[tex]\it a= \dfrac{2\sqrt3-2\sqrt2}{\sqrt7+1} = \dfrac{2(\sqrt3-\sqrt2)}{\sqrt7+1}
\\\;\\ \\\;\\
b=\dfrac{2\sqrt7+2}{\sqrt3-\sqrt2} =\dfrac{2(\sqrt7+1)}{\sqrt3-\sqrt2}[/tex]
[tex]\it m_g=\sqrt{a\cdot b} =\sqrt{\dfrac{2(\sqrt3-\sqrt2)}{\sqrt7+1}\cdot\dfrac{2(\sqrt7+1)}{\sqrt3-\sqrt2}} = \sqrt{2\cdot2} =\sqrt4=2[/tex]
