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Vikusik
a fost răspuns

demonstrati ca numarul[tex]4^{2n} + 2^{2n+1} +1[/tex] n∈N ,este patrat perfect.

Răspuns :

CarMina03
[tex]4^{2n} [/tex]+[tex] 2^{2n+1} [/tex]+1=([tex] 2^{n} [/tex])²+2*[tex] 2^{n} [/tex]*1+1²=([tex]2^{n} [/tex]+1)²-patrat perfect


am aplicat a²+2ab+b²=(a+b)²

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