Răspuns :
(x + 1 -3)(x+1+3) = (x-2)(x+4)
(2x + 1 -3)(2x+1+3) = (2x -2)(2x +4) = 4[(x-1)(x+2)]
(4x + 1 - 6)(4x + 1 + 6) = (4x -5)(4x + 7)
(2x + 1 -3)(2x+1+3) = (2x -2)(2x +4) = 4[(x-1)(x+2)]
(4x + 1 - 6)(4x + 1 + 6) = (4x -5)(4x + 7)