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a fost răspuns

fie functia [tex]f:R-\ \textgreater \ R, f(x)= \left \{ {{2x,xE(-{\displaystyle \infty };4]} \atop {2,xE(4; 8]}}\atop{ x^{2} ,xE(8;+{\displaystyle \infty)}}\right\}[/tex] .Calculati[tex]f(1)+f(2)+....f(10).[/tex].
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Răspuns :

Lennox
x∈(-∞,4]
f(1)=2*1=2
f(2)=2*2=4
f(3)=2*3=6
f(4)=2*4=8
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f(5)=f(6)=...=f(8)=2
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f(9)=9²=81
f(10)=10²=100
f(1)=f(2)+...+f(10)=2+4+6+8+4*2+81+100=209