PCl5 ⇄ PCl3 + Cl2
initial: [PCl5] = 2mol/l
reactioneaza x
la echilibru: (2-x) x x
" " " " " "" "" 0,5
2-x = 0,5 x = 1,5 Kc =[PCl3][Cl2]/[PCl5] = 1,5·1,5/0,5 = 4,5 mol/l
2. 28n + 71n = 148,5 99n = 148,5 n = 1,5 moli V = 0,5 l
CO + Cl2 ⇄ COCl2
initial : 1,5 moli 1,5 moli
reactioneaza: x
la echilibru: (1,5-x) (1,5 -x) x
" " " " " " " " 0,5
1,5 - x = 0,5 x = 1
%COtr. = x·100/1,5 = 66,66%
Kc=[COCl2]/{[CO]·[Cl2]} = (1/0,5)/[0,5/0,5]²} = 2 l/mol
