Răspuns :
Ma=(x+y)/2⇒17=(x+y)/2⇒x+y=17·2⇒x+y=34
39=(z+u)/2⇒z+u=39·2⇒z+u=78
Ma=(x+y+z+u)/4=(34+78)/4=112/4=28
39=(z+u)/2⇒z+u=39·2⇒z+u=78
Ma=(x+y+z+u)/4=(34+78)/4=112/4=28
[tex] \frac{x+y}{2}=17
[/tex]
x+y=17*2, x+y=34
[tex] \frac{z+u}{2}=39 [/tex]
z+u=39*2, z+u=78
x+y+z+u=78+34, x+y+z+u=112
[tex] \frac{x+y+z+u}{4}= \frac{112}{4} =28[/tex]
x+y=17*2, x+y=34
[tex] \frac{z+u}{2}=39 [/tex]
z+u=39*2, z+u=78
x+y+z+u=78+34, x+y+z+u=112
[tex] \frac{x+y+z+u}{4}= \frac{112}{4} =28[/tex]