2x+3>0 => x> -3/2
log[9]27=log[9]3*9=log[9]3+log[9]9=log[3²]3+1=1/2*log[3²]3²+1=1/2+1=3/2
log[1/4](2x+3)>3/2 Baza logaritmului e subunitara, se delogaritmeaza si se schimba sensul inegalitatii
2x+3<(1/4)^(3/2)
2x+3<1/2³
2x<1/8-3
x<- 23/16 si tinand cont de conditia pusa la inceput
-3/2<x<-23/16
