1mol.......................1mol
CaC2 + H2O-----> C2H2 + CaO M,CaC2= 64g/mol
64g..........................22,4l
x...............................8,96l
x,pur=25,6 g
p= m,purx100/m,impur
p=25,6x100/30=85,33%
CH≡CH + Br2------> CHBr=CHBr M,Br2= 160g/mol
22,4l.........160g
8,96l............x=64g Br2=md
c=mdx100.ms
2/100= 64/ms.....................calculeaza ms!!
Daca are loc bromurarea totala, cu 2Br2, reazultatul se dubleaza !!!!