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6[tex] x^{2} [/tex] - 8xy totul supra 9[tex] x^{2} [/tex] - 24xy+16[tex]y^{2} [/tex]
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Răspuns :

GreenEyes71
[tex]\dfrac{6x^2-8xy}{9x^2-24xy+16y^2}=\dfrac{2x(3x-4y)}{(3x)^2-2\cdot3x\cdot 4y+(4y)^2}=\dfrac{2x(3x-4y)}{(3x-4y)^2}=\dfrac{2x}{3x-4y}.[/tex]

Green eyes.


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