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a fost răspuns

fie x y z direct proportionale cu 2 3 6 .Aflati x y z daca x+2y+3z=260

Răspuns :

MariaLoredana1231
x,y,z d.p. 2,3,6
x+2y+3z=260
x/2=k, x=2k
y/3=k, y=3k
z/6=k, z=6k
Acum, inlocuim
2k+2*3k+3*6k=260
2k+6k+18k=260, 26k=260, k=260/26, k=10
x=2k, x=2*10, x=20
y=3k, y=3*10, y=30
z=6k, z=6*10, z=60
Sper ca te-am ajutat.....Succes!!

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