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Percys
a fost răspuns

A. 3(2x-1)-5(3x-1)=1
B. 4(x+4)=2(3x-1)+5
C. 3(y+4)-(-3+y)ori adica punct in misloc(-2)=3


OFER COROANA

Răspuns :

A. 3(2x-1)-5(3x-1)=1
6x-3-15x+5=1
-9x+2=1
9x=1
x=1:9

B. 4(x+4)=2(3x-1)+5
4x+26=6x-2+5
2x=23
x=23:2
C. 3(y+4)-(-3+y)*(-2)=3
3y+12-(6-2y)=3
3y+12-6+2y=3
5y=-9
y=-[tex] \frac{9}{3} [/tex]
Arina67
A. 3(2x-1)-5(3x-1)=1
(6x-3) - (15x-5)=1
6x - 3 -15x + 5=1
- 9x+2=1
- 9x=1- 2
-9х = -1
9х = 1
x = 1 : 9
х = ¹/₉
***************
B. 4(x+4)=2(3x-1)+5
4x + 16 = (6x - 2) + 5
4x + 16 = 6x - 2 + 5
4x + 16 = 6x + 3
4x - 6x = 3 - 16
- 2x = - 13
- x = (-13) : 2
x = ¹³/₂
x = 6 ¹/₂
x = 6,5
********************************
C. 3(y+4)-(-3+y)×(-2)=3
(3y+12) - (6-2y) = 3
3y +12 - 6 + 2y = 3
5y + 6 = 3
5y = 3 - 6
5y = - 3
y = (-3) : 5
y = -³/₅

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