Se considera p= \frac{ x^{2}+5x+6 }{x+2} , unde x este numar real, x \neq 2.
a) Aratati ca (x+2)(x+3)= x^{2} +5x+6.
b)Simplificati raportul prin (x+2).
x ∈ IR, x ≠ -2 [tex]p = \frac{x^2+5x+6}{x+2} \\ \\
a) x^2+5x+6 = x^2+2x+3x+6 = x(x+2)+3(x+2) \\
=(x+2)(x+3) \\ \\
b) p = \frac{x^2+5x+6}{x+2} = \frac{(x+2)(x+3)}{x+2} = x+3[/tex]
