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Calculati suma si diferenta numerelor a si b, stiind ca verifica relatiile : 1x2x3x4x5:4+64:(3xb-17)=46 si 100-4x[3x5+2x(5x6-16:4x3):6]-2x3=a

Răspuns :

Onilamarta17
64:(3*b-17)=46-120:4
64:(3*b-17)=46-30
64:(3*b-17)=16
3*b-17=64:16
3*b=4+17
b=21:3
b=7

100-4*[15+2*(30-4*3):6]-6=a
100-4*[15+2*(30-12):6]-6=a
100-4*(15+2*18:6)-6=a
100-4*(15+36:6)-6=a
100-4*(15+6)-6=a
100-4*21-6=a
100-84-6=a
16-6=a
a=10

64:(3•b-17)=46-120:4
64:(3•b-17)=46-30
64:(3•b-17)=16
3•b-17=64:16
3•b=4+17
b=21:3
b=7

a=100-4•[15+2•(30-4•3):6]-6
a=100-4•[15+2•(30-12):6]-6
a=100-4•(15+2•18:6)-6
a=100-4•(15+36:6)-6
a=100-4•(15+6)-6
a=100-4•21-6
a=100-84-6
a=16-6
a=10

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