sin105=(√6+√2)/4
Stii ca sin(A+B)=sinAcosB+cosAsinB
sin105
= sin(60+45)
= sin60cos45+cos60sin45
= √3/2*1/√2+1/2*1/√2
= (√3+1)/(2√2)*√2/√2
= (√6+√2)/4
