TOTAL MERE CULESE=,,a"
da bunicii jumatate=a/2
rest1=a-a/2=a/2
compot=2/3din a/2=2/3xa/2=2a/6=a//3
rest 2=a/2-a/3=numitor comun 6=(3a-2a)/6=a/6
fratele=2/7dina/6=2/7xa/6=2a/42=a/21
raman 5
deci 5+a/21+a/3+a/2=a
numitor comun 42
(5x42+2a+14a+21a)/42=42a/42
inmultim totul cu 42
210+37a=42a
42a-37a=210
5a=210
a=210:5
a=42
verificare
bunica 21
compot 2/3x21=14
raman 42-35=7
fratele 2/7x7=2
rest 5