Răspuns :
(8^29-3^27)=>
(2^3)^29-(3^9)^3
(2^29)^3-(3^9)^3 (cub perfect)
^ ridicat la putere
(2^3)^29-(3^9)^3
(2^29)^3-(3^9)^3 (cub perfect)
^ ridicat la putere
a=8[tex] 8^{29} -3^{27}=2^{3*29}-3^{3*9} =(2^{29} )^{3}- (3^{9})^{3} [/tex] este cub perfect