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Anamaria200889
a fost răspuns

Demonstrati ca 11este divizibil cu(2a+3a2+30)

Răspuns :

Deva
2a+3a2+30=2x10+a+3x100+ax10+2+30=
300+10(2+a)+(a+2)+30=330+(a+2)(10+1)=330+(a+2)x11=
11(30+a+2)=11(a+32):11=a+32

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