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Haidauemil
a fost răspuns

Cpsa ae rezolve ecuqtiile?
A)3^x+1+3^x=108
B)3^2x+1+3^2x-3^2x-1=29
c)2^x-1+2^x-3+2^x-4=448

Răspuns :

Renatemambouko
A)3^x+1+3^x=108
    3^x(3+1)=108
3^x=108/4=27=3³
x=3


c)2^x-1+2^x-3+2^x-4=448
(2^x-3)(2^2+1+2)=448
2^x-3=448/7=64 = 2^6
x-3=6
x=9

B)3^2x+1+3^2x-3^2x-1=29
(3^2x-1 ) (3^2+3-1)=29
(3^2x-1 ) ·11 =29
3^2x-1=29/11
aici e ceva gresit in exercitiu 

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