DC=AK deci AK=6
triunghi CKB e drept in K cu unghi BCK=30
sin 30=1/2
sin 30=KB/CB
deci 1/2=KB/CB deci 1/2=KB/8
deci KB=4
acum AB=AK+KB=6+4=10
cos30=rad3/2
cos30=CK/CB
rad3/2=CK/CB
rad3/2=CK/8
CK=8rad3/2
CK=4rad3
h=CK=8rad3
A=(B+b)*h/2
A=(6+10)*8rad3/2=16*8rad3/2=8*8rad3=64rad3
