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Valentina10000
a fost răspuns



Daca x/ y=3/5 aflati
5xy/2y la puterea2-x la puterea2 =;5x la puterea3 -y la putera3/y la putera3-3x la puterea3=;

Răspuns :

Emy78
x/y=3/5⇒x=3k, y=5k,
5xy/(2y²-x²)=5·3k·5k/(2·25·k² - 9k²)=45k²/41k²=45/41
(5x³-y³)/(y³-3x³)=(5·27k³-125k³)/(125k³-81k³)=10k³/44k³=10/44=5/22

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