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a fost răspuns

scrieti sub fractie ordinara ireductibila
a) 2,(3)
b)2,1(3)
plzzz

Răspuns :

a) 2, (3)= 2 (3/9)= 2 (1/3)= (6+1)/3 = 7/3
b) 2,1(3)=2  (13-1)/90= 2   12/90= 2   2/15= (30+2)/15= 32/15
a) 2,(3)=23-2/9=21/9 (simplificam prin 3) =7/3
b) 2,1(3)=213-21/90=192/90 (simplificam prin 2) = 96/45 (simplificam prin 3) = 32/15

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