Răspuns :
Al =Pb·a/2
260=4·10 ·a/2
a=260·2/40 ⇒ a=13 (apotema)
ab =apotema bazei
ab=AB/2 =10/2=5
a²=ab²+h² (t Pitagora in VOM)
13²=5²+h² ⇒h=12 (inaltimea)
m²=a²+(AB/2)² AB/2=MB
m²=13²+5²=169+25=194 m=√194 (muchia lat)
260=4·10 ·a/2
a=260·2/40 ⇒ a=13 (apotema)
ab =apotema bazei
ab=AB/2 =10/2=5
a²=ab²+h² (t Pitagora in VOM)
13²=5²+h² ⇒h=12 (inaltimea)
m²=a²+(AB/2)² AB/2=MB
m²=13²+5²=169+25=194 m=√194 (muchia lat)