-M,NaOH= (23gNa +16gO+1gH)/mol= 40g/mol
- prin regula de trei simpla:
40g ..............corespunde la 1 mol
300g...................................n= 300/23 mol=............................
-din relatia:
n= m/M
n= 300g/23g/mol=.............................calculeaza !!!
